Luas permukaan balok tersebut adalah … cm^2
a.378
b.159
c.756
d.318
bantu kaa pliss
a.378
b.159
c.756
d.318
bantu kaa pliss

Lp = 2(pl + pt + lt)
Lp = 2(9 × 6 + 9 × 7 + 6 × 7)
Lp = 2(54 + 63 + 42)
Lp = 2(117 + 42)
Lp = 2 × 159 cm²
Lp = 318 cm²
Diketahui :
Panjang = 9 cm
Lebar = 6 cm
Tinggi = 7 cm
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Ditanya :
Luas permukaan
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Jawab :
[tex] \rm Lp = 2 (P \times l) + (P \times t) + (l \times t) [/tex]
[tex] \rm Lp = 2 (9 \times 6) + (9 \times 7) + (6 \times 7) [/tex]
[tex] \rm Lp = 2 (54 + 63 + 42) [/tex]
[tex] \rm Lp = 2 (117 + 42) [/tex]
[tex] \rm Lp = 2(159) [/tex]
[tex] \rm Lp = (2 \times 159) [/tex]
[tex] \rm Lp = \bold{ {318~cm}^{2} } [/tex]
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Luas permukaan balok » 318 cm² (Opsi D)
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